Removed explicit VectorI::operator[]
Since Vector instances can be implicitely converted to T*, native operator[] will work on them Former-commit-id: 3f4a1822c514886dee7d9e5dab816c80e5c5ee99
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@@ -226,40 +226,6 @@ NzVector2<T>::operator const T*() const
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return &x;
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}
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template<typename T>
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T& NzVector2<T>::operator[](unsigned int i)
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{
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#if NAZARA_MATH_SAFE
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if (i >= 2)
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{
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NzStringStream ss;
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ss << "Index out of range: (" << i << " >= 2)";
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NazaraError(ss);
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throw std::domain_error(ss.ToString());
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}
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#endif
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return *(&x+i);
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}
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template<typename T>
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T NzVector2<T>::operator[](unsigned int i) const
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{
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#if NAZARA_MATH_SAFE
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if (i >= 2)
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{
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NzStringStream ss;
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ss << "Index out of range: (" << i << " >= 2)";
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NazaraError(ss);
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throw std::domain_error(ss.ToString());
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}
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#endif
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return *(&x+i);
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}
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template<typename T>
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const NzVector2<T>& NzVector2<T>::operator+() const
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{
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